Question

prove that: sin2θ+sin2θ⋅tan2θ=tan2θ without using p b and h relations​

Answer 1

Answer:

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Step-by-step explanation:

tan

2

θ−sin

2

θ=tan

2

θ×sin

2

θ

cos

2

θ

sin

2

θ

−sin

2

θ

=

cos

2

θ

(sin

2

θ−sin

2

θcos

2

θ)

=

cos

2

θ

sin

2

θ

(1−cos

2

θ)

=tan

2

θsin

2

θ (proved)