Prove that sin² theta/cos Theta +cos theta =sec theta
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Answered by
3
Answer:
Answer
To prove:
(sinθ+cosecθ)
2
+(cosθ+secθ)
2
=7+tan
2
θ+cot
2
θ
Solution:
L.H.S. =(sinθ+cosecθ)
2
+(cosθ+secθ)
2
=sin
2
θ+cosec
2
θ+2sinθ.cosecθ+cos
2
θ+sec
2
θ+2cosθ.secθ
=(sin
2
θ+cos
2
θ)+1+cot
2
θ+2+1+tan
2
θ+2
=1+6+tan
2
θ+cot
2
θ
=7+tan
2
θ+cot
2
θ
= R.H.S.
Answered by
1
HOPE YOU UNDERSTOOD THE SOLUTION
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