prove that sin20 sin40 sin60 sin80 = 3/16
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Hey Dear that's your answer:-
Sin60(sin20 .sin40.sin80)
√3/2( sin20.sin(60-20).sin(60+20)
√3/2(sin3(20)/4)
√3/2(sin60/4
√3/2(√3/2*4 )
√3/2(√3/8)
=3/16
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Sin60(sin20 .sin40.sin80)
√3/2( sin20.sin(60-20).sin(60+20)
√3/2(sin3(20)/4)
√3/2(sin60/4
√3/2(√3/2*4 )
√3/2(√3/8)
=3/16
Mark as brainleast.
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