Question

prove that sin²56°-cos²34°=0

Answer 1

hey your ans is here

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given

sin^2 56°-cos^2 34°=0
to prove it

now
we know
that sin(90-a)=cosa
here a is any number
so

sin2(90-56)-cos2 34
cos2 34 -cos2 34=0

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Answer 2

Heya!!

Here is your answer

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R.T.P :-

${ sin }^{2} 56 - {cos}^{2} 34 = 0$

Using the identity :-

cos (90-ø ) = sin ø

→ cos^2 34 can be written as cos^2 (90-56) = sin^2 56

${sin}^{2} 56 - {sin}^{2} 56 \\ \\ 56 - 56 = 0$

Hence proved

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Glad if helped !!