prove that sin2A=2sinA when A=0, 30,45,60
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Answered by
4
Answer:
A = 0°
Step-by-step explanation:
sin 2A=2 sin A
if A = 0°
sin 2A = sin 2 x 0° = sin 0° = 0
and 2 sin A= 2 sin 0° = 2 x 0 = 0
I hope this help you
ll welcome ll
Answered by
145
=> sin2A=2sinA
=>2sinA.cosA-2sinA =0
=>2sinA(cosA-1)=0
=>either 2sinA=0
=>sinA=0
=>sinA=sin0°
=>A= 0°
=>or cosA -1=0
=>cosA=1
=>cosA=cos 0°
=>
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