Math, asked by krishan427384kk, 7 months ago

prove that sin2A=2sinA when A=0, 30,45,60​

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Answered by ankitsaini76216
4

Answer:

A = 0°

Step-by-step explanation:

sin 2A=2 sin A

if A = 0°

sin 2A = sin 2 x 0° = sin 0° = 0

and 2 sin A= 2 sin 0° = 2 x 0 = 0

I hope this help you

ll welcome ll

Answered by Anonymous
145

\bold{\huge{\fbox{\color{Maroon}{♡Hello♡}}}}

=> sin2A=2sinA

=>2sinA.cosA-2sinA =0

=>2sinA(cosA-1)=0

=>either 2sinA=0

=>sinA=0

=>sinA=sin0°

=>A= 0°

=>or cosA -1=0

=>cosA=1

=>cosA=cos 0°

=>\bold{\small{\fbox{\color{Black}{A=0°}}}}

\bold{\huge{\fbox{\color{Purple}{♡Thanks♡}}}}

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