Question

Prove that sin²A + cos²A=1​

Answer 1

Answer:

Step-by-step explanation:

In a triangle ABC , right angled at B

=AB square+BC square= AC square(1)

= Divide each term of eqn(1) by AC square

= AB square/AC sqaure+BC square/AC square = AC square/ AC square

= (Cos A) sqaure + (SinA) square=AC sqaure/AC square(Using applications of trignometry)

Cos square A + Sin square A = 1

Answer 2

Answer:

Refer to the attachment...