prove that sin2a+cos2a is equal to one
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Answered by
0
Answer:
Step-by-step explanation:
Hey there!
L.H.S
=sin2A/1-cos2A
= 2sinAcosA/1-(1-2sin²A)
= 2sinAcosA/2sin²A
=cosA/sinA
=cotA
=R.H.S
hope helped !!
Answered by
0
Step-by-step explanation:
In a right angled triangle ABC, with angle B = 90°,
sinA=BC/AC and cosA=AB/AC
angle B=90°
By Pythagoras theorem,
AB²+BC²=AC²
sin²A+cos²A=(BC/AC)²+(AB/AC)²
=AB²+BC²/AC²
=AC²/AC²
=1
Hence proved.
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