Math, asked by Lalitasarate, 8 months ago

Prove that:
Sin²A. Cos²B + Cos² A. Sin²B
+ cos²A. Cos²B + Sin²A. Sin2 B = 1​

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Answers

Answered by jatinsharma12
3

Answer:

STEP BY STEP EXPLANATION

sin²A{cos²B+sin²B} + cos²A {sin²B + cos²B}

SIN²A(1) +COS²A(1)

SIN²A + COS²A

= 1

LHS = RHS

HENCE PROVED

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