Question

prove that. Sin²B- Sin²C = Sin(B+C) sin(B-C)​

Answer 1

Answer:

To prove:

Sinsquare B- Sinsquare C = Sin(B+C) Sin(B-C)

Now

here is a formula required

i.e asquare - bsquare = (a+b) (a-b)

so now according to question

=Sin square B- Sin square C

=(SinB+SinC) (SinB-SinC)

=Sin(B+C) Sin(B-C) HP

That's all hope it helps you*****