Question

Prove that sin²Ø + cos²Ø = 1​

Answer 1

Answer:

Let a, b, c be lengths of right angled triangle

By definition

sinθ=b/c(

hypotenuse

opposite side

)

cosθ=a/c(

hypotenuse

adjacent side

)

sin

2

θ+cos

2

θ=

c

2

b

2

+

c

2

a

2

=

c

2

a

2

+b

2

From Pythagoras theorem

c

2

=a

2

+b

2

∴

c

2

a

2

+b

2

=1

sin

2

θ+cos

2

θ=1

Hence, proved.

Hope it helps u

Answer 2

Answer:

Done

Step-by-step explanation:

Sin^2 theta=(perpendicular/hypotenuse)^2

And cos^2 theta=(base/hypotenuse) ^2

Now perpendicular^2+base^2=hypotenuse^2

So sin^2 theta+cos^theta=1

Done