prove that sin²theta + cos²theta = 1
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Answer:
sin^2theta+cos^2theta=1
Step-by-step explanation:
in a triangle- a^2+b^2=c^2
= AB^2+BC^2=AC^2
= AB^2/AC^2+BC^2/AC^2=AC^2/AC^2
= AB^2/AC^2+BC^2+AC^2=1 --1
Perpendicular(P)/Hypo(H)=sin theta
Base(B)/Hypo(H)=cos theta
from --1
sin ^2 theta + cos^2 theta = 1
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