prove that sin2theta=tan2theta/sec2heta
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(sec2theta - sin2theta )/ tan2theta = [(1/cos2theta) - sin2theta]/[ sin2theta/cos2theta]
=[1-sin2theta cos2theta]/ [sin2theta]
=[1/sin2theta]- [sin2theta cos2theta/sin2theta]
=cosec2theta-cos2theta
Hence proved.
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