Math, asked by sunderrentele, 9 months ago

prove that sin2theta=tan2theta/sec2heta

Answers

Answered by mail2arnav30

0

Answer:

(sec2theta - sin2theta )/ tan2theta = [(1/cos2theta) - sin2theta]/[ sin2theta/cos2theta]

=[1-sin2theta cos2theta]/ [sin2theta]

=[1/sin2theta]- [sin2theta cos2theta/sin2theta]

=cosec2theta-cos2theta

Hence proved.

Step-by-step explanation:

Answered by vikassharma1052

0

Answer:

Step-by-step explanation:

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