Question

prove that sin2theta upon cos theta = sec theta

Answer 1

$\mathtt\:\\l.h.s\\ \frac{ {sin}^{2}theta }{ {cos} \: theta } + cos \: theta \: \\ \\ \frac{ {sin}^{2} + {cos}^{2} }{cos} \\ \\ \frac{1}{cos} \: \: \: ({ {sin}^{2} + {cos}^{2} =1 }) \\ \\ sec \: \: theta \: \: \: ( \frac{1}{cos} = sec) \\ \\ r.h.s = sec \: \: theta \\ \\ therefore \: l.h.s= r.s.h \\ \\ proved.$
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Answer 2

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