Question

prove that sin²x + cos²= 1

Answer 1

As we know that...in a triangle there is perpendicular (p) ,base (b) and hypotenuses (h).
Now,sin x = p/h and,
cos x = b/h .
so, LHS→ sin²x + cos²x
= (p/h )² + (b/h)²
= p²/h² + b²/h²
= (p² + b²)/h²
= h²/h² ........[p²+b²= h²]
= 1

Answer 2

I am assuming it as sin²θ+cos²θ=1.