prove that ➡(sin35/cos55)²+[cos55/sin35]²-2cos60=1
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Answered by
4
Answer:
(sin35/cos55)²+(cos55/sin35)²-2cos60
=[cos(90-35)/cos55]²+[cos55/cos(90-35)]²-2cos60
=(cos55/cos 55)²+(cos55/cos 55)²-2cos60
=1+1-2×1\2
=1+1-1
=1
Answered by
1
Answer:-
L.H.S
=[sin 35/sin(90-55)]²+[cos 55/cos(90-35)]²-2 cos 60
=[sin 35/sin35]²+[cos 55/cos 55]²-2 (1/2) {∵ cos 60°=1/2}
=[1]²+[1]²-1
=2-1
=1
L.H.S =R.H.S
HENCE PROVED
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