Question

Prove that Sin3A +Sin7A +Sin10A = 4Sin5A time Cos7A/2 time cos 3A/2
$\sin(3a) + \sin(7a) + \sin(10a) = 4 \sin(5a) \times \cos(7a \div 2) \times \cos(3a \div 2 )$
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Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

kindly refer the solution