Question

Prove that:
sin⁴theta-cos⁴theta=2sin²theta-1

Answer 1

L.H.S:-

sin⁴∅-cos⁴∅

= (sin²∅+cos²∅)(sin²∅-cos²∅)

= 1 ( sin²∅-cos²∅)

= sin²∅-cos²∅

R.H.S:-

2sin²∅-1

= 2sin²∅-(sin²∅+cos²∅)

=2sin²∅-sin²∅-cos²∅

=sin²∅-cos²∅

L.H.S=R.H.S [ proved]

Answer 2

Answer:

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