prove that sin50-sin70+sin10=0
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Answered by
4
(sin50-sin70)+sin10=0
apply sin10 for both numbers
(sin50+sin10)+(-sin70+sin10)=0
sin60+(-sin60)=0
sin60-sin60=0
(root3/2)+(-root3/2)=0
root 3/2 is cancelled
0=0
hence proved.
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sprao534:
totally wrong.
Which
why
Answered by
7
=2cos60°sin(-10)°+sin10°
Since sinc-sind
=2cos(c+d)/2. sin(c-d)/2
=2(1/2)(-sin10)+sin10°
=-sin10°+sin10
=0
Since sinc-sind
=2cos(c+d)/2. sin(c-d)/2
=2(1/2)(-sin10)+sin10°
=-sin10°+sin10
=0
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