prove that
sin5xcos2x + cos6xsin3x=sin8xcosx
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Sin5x.Cos2x + Cos6x.Sin3x
=1/2(2.Cos2x.Sin5x + 2.Cos6x.Sin3x)
=1/2{(Sin7x+Cos3x)+(Sin9x-Cos3x)
=1/2{Sin7x+Cos3x+Sin9x-Cos3x}
=1/2{Sin9x+Sin7x)
=1/2{2.Sin(9x+7x)/2. Cos (9x-7x)/2}
=1/2{2.Sin8x.Cosx}
= Sin8x.Cosx[PROOVED]
Explanation
In The 2nd Line[2CosA SinB]Formula
5Th Line [SinC+SinD]Formula
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