Prove that sin60degree= (2tan30degree)/(1+tan^2 30degree)
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Solution
L.H.S → sin 60°
R.H.S → 2 tan 30°/(1 + tan² 30°)
- tan 30° = 1/√3
- sin 60° = √3/2
→ (2 × 1/√3)/(1 + 1/√3²)
→ (2/√3)/(1 + 1/3)
(っ.❛ ᴗ ❛.)っ
On rationalizing 2/√3 we get
→ 2/√3 × √3/√3 = 2√3/3
→ 2√3/3 ÷ 4/3
→ 2√3/3 × 3/4
→ √3/2 = sin 60° = L.H.S
Q.E.D
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