Math, asked by deepavashistha776, 8 months ago

prove that sin6A+cos6A+3sin²Acos²A=1

Answers

Answered by llɱissMaɠiciaŋll

14

Step-by-step explanation:

sin^6A+cos^6A

(sin²A)³+(cos²A)³ ............[a^6=(a²)³]

(sin²A+cos²A)³-3sin²Acos²A.........[(a+b)³=a³+b³+3ab]

1³-3sin²Acos²A

1-3sin²Acos²A

!!hence proved!!

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