prove that: sin70*sec20=0
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Answered by
8
HELLO DEAR,
we know that:-
sin(90° - ∅) = cos∅
sin70° × sec20°
=> Sin(90 - 20)° ×sec20°
=> Cos20° × sec20°
=> Cos20° × 1/cos20°
=> 1
we know that:-
sin(90° - ∅) = cos∅
sin70° × sec20°
=> Sin(90 - 20)° ×sec20°
=> Cos20° × sec20°
=> Cos20° × 1/cos20°
=> 1
Answered by
4
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