Math, asked by anshitabhowmich011, 6 months ago

prove that sin8x = 8sinx.Cosx.Cos2x.Cos4x

Answers

Answered by divyes1289

2

Answer:

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Step-by-step explanation:

Apply the 2 trig identity: sin 2a = 2sin a.cos a sin 8x = 2sin 4x.cos 4x. Since sin 4x = 2sin 2x.cos 2x, therefor, sin 8x = 2(2sin 2x.cos 2x)cos 4x =

Answered by pranabbhowmick06

0

Step-by-step explanation:

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