prove that sina+1-cosa÷cosa-1+sina=1+sina÷cosa
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Hope it will help u see the pic
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Meriko:
RHS is in sin ansd cos not in sec and tan
sorry actually I m in class now wait
okay then
sorry Google it out
my first method is correct
may be there is +, -, mistake in question printing
okay
The question is absolutely correct
There is no sign mistake
And also I got the answer
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Step-by-step explanation:
=(sinA + 1 - cosA) / (cosA - 1 + sinA)
Divide each term by cosA
=(tanA + secA - 1) / (1 - secA + tanA)
=[tanA + secA - ( 2−2)] /
( 1 - secA + tanA)
= (tanA+secA)( 1 - secA + tanA )/(1 - secA + tanA)
= tanA + secA
= (sinA / cosA )+ 1 / cosA
= (sinA + 1 )/ cosA
Hence Proved
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