prove that sina/1+cosa + sina/1-cosa = 2/sina
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Answer:
L.H.S. =sinA1+cosA+1+cosAsinA
=sinA(1+cosA)(1+cosA)(1+cosA)+sinAsinA
=(1+cosA)sinA(1+cosA)2+sin2A
=(1+cosA)sinA1+cos2A+2cosA+sin2A
=(1+cosA)sinA1+2cosA+1
=(1+cosA)sinA2+2cosA
=(1+cosA)sinA2(1+cosA)
=2sinA1
=2cosecA
=R.H.S
Hence proved.
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