Question

Prove that : (sinA+1+cosA) (sinA-1+cosA). secAcosecA = 2​

Answer 1

Answer:

Explanation:

(SinA+1+cosA) (sinA-1+cosA)=2/secAcosA

Sin2A-sinA+sinAcosA+sinA-1+cosA+sinAcosA-cosA+cos2A

1-1 +2sinAcosA

2sinAcosA

2(1/cosecA*1/sec )

2/secAcosA

Hence prove

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