Question

prove that sinA=1/cosecA

Answer 1

sinA = P/H
P = Perpendicular
H = Hypotenuse
Cosec = H/P
so it's proved

Answer 2

sin A is equal to front side of the 90 degree triangle of that A angle by max side,
and cosec A is equal to max side by front side so both of inverse of each other
so sine A= 1/ cosec A