prove that sinA/1+cotA-cosA/1+tanA=sinA-cosA
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Step-by-step explanation:
SinA/(1+CosA/SinA) - CosA/(1+SinA/CosA)
{Sin²A/SinA+CosA} - {Cos²A/SinA+CosA}
(Sin²A - Cos²A)/(SinA+CosA)
(SinA-CosA)(SinA+CosA) / (SinA+CosA)
SinA - CosA
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