Question

prove that : sinA./1+cotA- cosA/1+tanA = sinA-cosA​

Answer 1

Step-by-step explanation:

$\frac{sinA}{1 + cotA} - \frac{cosA}{1 + tanA} \\ \\ = \frac{ {sin}^{2} A}{sinA + cosA} - \frac{ {cos}^{2}A }{cosA + sinA} \\ \\ = \frac{ {sin}^{2}A - {cos}^{2} A }{sinA + cosA} \\ \\ = sinA - cosA$.