Math, asked by Adisharma1409, 1 year ago

prove that sinA(1+tanA) + cosA(1+cotA) =secA+cosecA​

Answers

Answered by Sehaj2810
5

Answer:

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sin(1+sin/cos)+cos(1+cos/sin)

sin(cos+sin/cos)+cos(sin+cos/sin)

(sin+cos)(sin/cos+cos/sin)

(sin+cos)/(sincos)

1/cos+1/sin

sec+cosec

Answered by sharonr
0

sin\ A(1+tan\ A) + cos\ A(1+cot\ A) = sec\ A + cosec\ A

Solution:

Given that, we have to prove:

sin\ A(1+tan\ A) + cos\ A(1+cot\ A) = sec\ A + cosec\ A

Take LHS

sin\ A(1+tan\ A) + cos\ A(1+cot\ A) \\\\sin\ A(1 + \frac{sin\ A}{cos\ A}) +  cos\ A(1+ \frac{cos\ A}{sin\ A})\\\\ \frac{sin\ A}{cos\ A} ( sin\ A + cos\ A) + \frac{cos\ A}{sin\ A} (sin\ A + cos\ A)\\\\( sin\ A + cos\ A) [ \frac{sin\ A}{cos\ A}+ \frac{cos\ A}{sin\ A}]\\\\( sin\ A + cos\ A) [ \frac{sin^2 A+ cos^2 A}{sinA\ cos\ A}]\\\\

( sin\ A + cos\ A) [ \frac{1}{sinA\ cos\ A}]\\\\\frac{sin\ A}{sin\ A\ cos\ A} + \frac{cos\ A}{sin\ A\ cos\ A}\\\\\frac{1}{cos\ A} + \frac{1}{sin\ A}\\\\sec\ A + cosec\ A\\\\Thus\\\\

LHS = RHS\\\\THUS\ PROVED

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