Prove that SinA-2sin^3A/2cos3A-cosA=tanA
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Step-by-step explanation:
sina(1 - 2sin²a) / cosa(2cos²a - 1)
sina(1 - 2(1 - cos²a)) / cosa(2cos²A - 1)
sina(1 - 2 + 2cos²a) / cosa(2cos²a - 1)
sina(2cos²a - 1) / cosa(2cos²a - 1)
∴sina/cosa = tana
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Anonymous:
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