Math, asked by durga5742, 7 months ago

Prove that
SinA
(9) cos (45°- A) - sin (45° -- A) = sin2A
1 + tan (45° B)
1 - tanº (45° - B)
cosec2B
(s)
sin A cos2A
sin 4A sec A
(0
4 cosec 2A. cot 2A = cosec-A - sec

Answers

Answered by mahatoseema50

1

Step-by-step explanation:

I think so long explanation ...

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