prove that .sinA×cos(90-A)cosA/sin(90-A) + cosA×sin(90-A)sinA/cos(90-A) = 1
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Answer:
According to Trigonometric Formulas,
⇒ Sin A = Cos ( 90 - A )
⇒ Cos A = Sin ( 90 - A )
According to the question,
⇒ Cos A / Sin ( 90 - A ) + Sin A / Cos ( 90 - A ) = 2
Considering LHS we get,
⇒ Cos A / Sin ( 90 - A ) + Sin A / Cos ( 90 - A )
Rewriting the above equation with the trigonometric formulas, we get
⇒ Cos A / Cos A + Sin A / Sin A
⇒ 1 + 1
⇒ 2
Hence LHS = RHS
Hence Proved !!
Hope it helped !!
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