Math, asked by dkalita45, 1 year ago

prove that sinA + cos(90° + A) + tan(180° + A) + cot(270° + A) = 0

Answers

Answered by kartikChhabra

2

We now that cos(90+A) = -sinA (b'coz in second quadrant

tan(180+A) = tanA (b'coz in third quadrant )

cot (270+A)= -tanA (b'coz in fourth quadrant)

put all the value in equation

sinA-sinA+tanA-tanA=0 ANSWER

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