Question

prove that sinA + cos(90° + A) + tan(180° + A) + cot(270° + A) = 0 ​

Answer 1

We now that cos(90+A) = -sinA (b'coz in second quadrant

tan(180+A) = tanA (b'coz in third quadrant )

cot (270+A)= -tanA (b'coz in fourth quadrant)

put all the value in equation

sinA-sinA+tanA-tanA=0 ANSWER