prove that sinA+cosA=1
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that is wrong question
sin^2 + cos^2 = 1
as cos = B/H
and sin = P/H
so there square sum are
(P/H)^2 + (B/H)^2 = (H/H)^2
H/H cancel and become 1
Here H = Hypotenuse
P = Perpendicular
B = Base
sin^2 + cos^2 = 1
as cos = B/H
and sin = P/H
so there square sum are
(P/H)^2 + (B/H)^2 = (H/H)^2
H/H cancel and become 1
Here H = Hypotenuse
P = Perpendicular
B = Base
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