Prove that: SinA - cosA+ 1/ sinA+cosA-1=1 / secA-tanA
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Step-by-step explanation:
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Answer:LHS=RHS
Step-by-step explanation:
LHS = sinA - cosA+1/sinA +cosA -1
= tanA -1 +secA / tanA+1 - secA ------------------- (Dividing by cos θ )
= (tanA +secA)-1 / (tanA-secA)+1
= {(tanA+secA-1)}(tanA-secA) / {(tanA+secA +1)}(tanA-secA)
=(tan^2 A -sec^2 A) - (tanA - secA) / (tanA + secA +1)(tanA - secA)
=-1-tanA+secA / (tanA+ secA +1) (tanA -secA)
=-1 / tanA-secA
= 1 / secA -tanA=RHS
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