Prove that (SinA+CosA)(1-SinACosA)=Sin^3A+Cos^3A
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Answered by
1
Step-by-step explanation:
we know that,
- (a+b)^3=a^3+b^3+3ab(a+b)
- a^3+b^3=(a+b)^3-3ab(a+b)
- sin^3A+cos^A=(sinA+cosA)^3-3sinAcosA(sinA+cosA)
Hope you understand this answer
Answered by
2
Answer:
Sin^3A+cos^3A= (sinA+cosA)(1- sinAcosA) ... or (sinA-cos^2 AsinA + cosA-sin^2 AcosA)/(sinA + cosA) ... of ant two points Q1 and Q2 are (x1,y1) and (x2,y2), respectively ...
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