Math, asked by rockstarruchir007, 10 months ago

Prove that (SinA+CosA)(1-SinACosA)=Sin^3A+Cos^3A​

Answers

Answered by pravalika7954
1

Step-by-step explanation:

we know that,

  • (a+b)^3=a^3+b^3+3ab(a+b)
  • a^3+b^3=(a+b)^3-3ab(a+b)
  • sin^3A+cos^A=(sinA+cosA)^3-3sinAcosA(sinA+cosA)

Hope you understand this answer

Answered by vkpathak2671
2

Answer:

Sin^3A+cos^3A= (sinA+cosA)(1- sinAcosA) ... or (sinA-cos^2 AsinA + cosA-sin^2 AcosA)/(sinA + cosA) ... of ant two points Q1 and Q2 are (x1,y1) and (x2,y2), respectively ...

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