prove that (sinA+cosA)× (1-sinAcosA)=sin^3A+cos^3A
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LHS
= (sinA + cosA)(1 - sinAcosA)
= (sinA) - (sin²AcosA) + (cosA) - (sinAcos²A)
= sinA - sinAcos²A + cosA - sin²AcosA
= sinA(1 - cos²A) + cosA(1 - sin²A)
= sinAsin²A + cosA²cos²A
= sin³A + cos³A
= R.H.S.
Hence Proved !!!
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