Question

Prove that
(sinA+cosA)^2-(sinA-cosA)^2=2sin2A.cos2A

Please don't give answers as I don't know and others....​

Answer 1

Step-by-step explanation:

LHS

sin^2 A + 2 Sin A cos A + cos^2 A -[sin^2 A - 2 sin A cosA +cos^2A]

sin^2 A + 2 Sin A cos A + cos^2 A -sin^2 A + 2 sin A cosA -cos^2A

2 Sin A cos A + 2 Sin A cos A

2sin2A.cos2A

LHS = RHS

Hence Proved

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