Question

prove that sinA +cosA = cosA/1-tanA + sinA / 1- cotA​

Answer 1

Answer:

just change rhs by putting tanA=sinA/cosA and put cotA=cosA/sinA and then solve....hope this helps

Answer 2

$\frac{sinA}{1 - cotA} + \frac{cosA}{1 - tanA} \\ \\ = \frac{ {sin}^{2}A }{sinA - cosA} + \frac{ {cos}^{2}A }{cosA - sinA} \\ \\ = \frac{ {sin}^{2}A }{sinA - cosA} - \frac{ {cos}^{2} A}{sinA - cosA} \\ \\ = \frac{ {sin}^{2}A - {cos}^{2} A}{sinA - cosA} \\ \\ = sinA + cosA$