Math, asked by MATHSACHI, 1 month ago

Prove that sinA+cosA/secA+cosecA= sinA.cosA

Answers

Answered by neladridinda2008

1

Answer:

Step-by-step explanation:

LHS:

secA + cosecA = 1/cosA + 1/sinA = sinA+cosA/sinAcosA

so sinA+cosA/secA+cosecA = sinA+cosA/(sinA+cosA/sinAcosA) = sinAcosA

RHS: sinAcosA

so LHS=RHS...Hence proved

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