Math, asked by girishsoni198, 8 months ago

Prove that
(sinA+cosA)(tanA+cotA)=secA+cosecA.

Answers

Answered by gulafshaxc270505

1

Answer:

sinA+cosA ) ( sinA/cosA+cosA/sinA)

(sinA+cosA) ( sinA+cosA/cosASinA)

sin squareA+cos squareA/cosA+sinA

1/cosA+sinA

secA+cosecA

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