Question

Prove that (sinA+ cosec A)^2 + (cosA+ secA)2 = 7 + tan^2A+ cot^2A​

Answer 1

Answer:

PLS MARK ME AS BRAINLY...AND FOLLOW ME IF UR INTRESTED.....AND GIVE ME A LIKE .....

HOPE IT WAS HELPFUL...BHAIYA..... ...

BYEEE

Answer 2

Step-by-step explanation:

Using (a+b)² = a²+b²+2ab

sin²A + cosec²A + 2sinAcosecA + cos²A + sec²A + 2cosAsecA

(Rearranging)

sin²A + cos²A + cosec²A + sec²A + 2sinAcosecA + 2cosAsecA

Using sin²A+cos²A = 1, cosec²A = 1+cot²A and sec²A = 1+tan²A

1 + 1 + cot²A + 1 + tan²A + 2sinA×1/sinA + 2cosA×1/cosA

3 + tan²A + cot²A + 2 + 2

7 + tan²A + cot²A

HENCE PROVED

MARK AS BRAINLIEST PLEASE