prove that (sina+coseca)^2=7+tan^2a+cot^2a
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Step-by-step explanation:
To Prove :- ( SinA+CosecA)2+(CosA+SecA)2=7+tan 2A+Cot2A
LHS= (SinA+CosecA)2+(CosA+SecA)2
= Sin2A+Cosec2A+2SinA CosecA+ Cosec2A+Sec2A+2CosA SecA
= Sin2A+ Cos2A+2+Cosec2A+Sec2A+2
= 1+4+Cosec2A+Sec2A
5+1+Cot2A+1+Tan2A
7+Co2A+Tan2A
Hence Proved.
Answerd by Lakshita Kumar .
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