Question

Prove that , sinA /secA + 1 + sinA /secA -1 = 2cotA

Answer 1

Answer:

Step-by-step explanation:

sinA /secA + 1 + sinA /secA -1

= SinA(SecA - 1) + SinA(SecA + 1)/ (SecA - 1)(SecA + 1)

= SinASecA - SinA + SinASecA + SinA / Sec²A - 1

= 2SinASecA/ Tan²A  (∵ Sec²A - Tan²A = 1)

= 2SinASecA/Sin²A/Cos²A

= 2SinA*Cos²A / Sin²A . CosA  (∵ SecA  = 1/CosA)

= 2 CosA/SinA

= 2 CotA

= R.H.S

Hence proved

Answer 2

Here u go

Refer the attachment

Hope it helps u...

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