prove that
SinA/SecA + TanA - 1 + CosA/CosecA + CotA - 1 = 1
anybody help please
Answers
Answer:
sinA/secA+tanA-1+cosA/cosecA+cotA-1
=sinA/(1/cosA+sinA/cosA-1)+cosA/(1/sinA+cosA/sinA-1)
=sinA/{(1+sinA-cosA)/cosA}+cosA/{(1+cosA-sinA)/sinA}
=sinAcosA/(1+sinA-cosA)+sinAcosA/(1+cosA-sinA)
=sinAcosA[(1+cosA-sinA+1+sinA-cosA)/(1+sinA-cosA)(1+cosA-sinA)]
=2sinAcosA/(1+sinA-cosA+cosA+sinAcosA-cos²A-sinA-sin²A+sinAcosA)
=2sinAcosA/{1+2sinAcosA-(sin²A+cos²A)}
=2sinAcosA/(1+2sinAcosA-1)
=2sinAcosA/2sinAcosA
=1 (Proved)
Step-by-step explanation:
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Step-by-step explanation:
First you will put the value of Tan A-1 and Cot A-1
that is Sec A and Cosec A so it will cut each other and the remaining is Sin A + Cos A that is equal to 1
And yo do not understand So see the image
