Question

prove that sinA sin(B-C) + sinB sin(C-A) + sinC sin(A-B) = 0​

Answer 1

Answer:

hope this helps  u  

Step-by-step explanation:

SinA . Sin(B - C) + SinB . Sin(C - A) + SinC . Sin(A - B)=0

=>SinA . (SinBCosC - CosBSinC) + SinB . (SinCCosA - CosCSinA) + SinC . (SinACosB - CosASinB)

=>SinASinBCosC SinACosBSinC+ SinBSinCCosA- SinBCosCSinA+ SinCSinACosB - SinCCosASinB

All get cancelled

=>0

Hence Proved