Math, asked by nimrazuberi9, 11 months ago

Prove that Sina=sin3a/1+2cos2a,then find sin15

Answers

Answered by pradeepsingh1372
13

Step-by-step explanation:

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Answered by suchindraraut17
8

sin15 = \frac{1}{2\sqrt2}

Step-by-step explanation:

We have to prove that,sina = \frac{sin3a}{1+2cos2a}

(sina)(1+2cos2a) = sin3a

By Taking L.H.S.,

sina(1+ cos 2a)

= sina(1+2(1-2sin^2a))

= sina(1+2-4sin^2a)

=sina(3-4sin^2a)

=3sina-4sin^3a

= sin3a

=R.H.S.

Now,We have to find,sin15°

By using this formula,

sina = \frac{sin3a}{1+2cos2a}

sin(15) = \frac{sin3.15}{1+2cos2.15}

        =\frac{sin45}{1+2cos30}

        =\frac{1/\sqrt(2)}{1+2\times\frac{1}{2}}

      = \frac{1}{2\sqrt2}

       

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