Question

Prove that sinA +sinB / cosA + sin B = tan(A-B/2) cot(A+B/2)

Answer 1

Step-by-step explanation:

sinA=m sinB

sinA/sinB=m

Using compendo dividendo:

(sinA+sinB) /(sinA-sinB) =(m+1) /(m-1).. 1

sinA +sinB=

2sin(A+B) /2.cos(A-B) /2 …2

sinA-sinB =2cos(A+B) /2.sin(A-B) /2..3

Hence from (1), (2), and(3) :

tan(A+B) /2) /tan(A-B) /2) =m+1/m-1