Question

prove that sinA-tanA/1-cosA=1+secA​

Answer 1

Answer:

Here

Step-by-step explanation:

sin A tan A/(1-cos A)

= sin^2 A/cos A(1- cos A)

= (1-cos^2 A)/cos A(1- cos A)

= (1+cos A)(1-cos A)/cos A(1- cos A)

= (1+cos A)/cos A

= sec A + 1