Math, asked by Ungav, 8 months ago

prove that sinA-tanA/1-cosA=1+secA

Answers

Answered by inspirationalgdandyt

1

Answer:

Here

Step-by-step explanation:

sin A tan A/(1-cos A)

= sin^2 A/cos A(1- cos A)

= (1-cos^2 A)/cos A(1- cos A)

= (1+cos A)(1-cos A)/cos A(1- cos A)

= (1+cos A)/cos A

= sec A + 1

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